3.73: Binomial expansion beginning b4+48b3xb^{4} + 48b^{3}x

0606/22/F/M/24 — Question 10 · 10 marks · Binomial

The expansion of (a+xa)n\left(a + \dfrac{x}{a}\right)^{n} in ascending powers of xx begins b4+48b3xb^{4} + 48b^{3}x, where nn, aa and bb are positive integers.
(a)
Show that an24=(48n)2a^{\frac{n}{2} - 4} = \left(\dfrac{48}{n}\right)^{2}.
[4]
(b)
Given also that the third term is 1056b2x21056b^{2}x^{2}, find the values of nn, aa and bb.
[6]