Additional Mathematics 0606 / Series / 1.41.4: Binomial expansion and coefficient of x7x^7x70606/11/O/N/16 — Question 4 · 5 marks · BinomialMark as done · Save for later · Show all solutions(i)Find the first 3 terms in the expansion of (2x2−13x)5\left(2x^{2} - \tfrac{1}{3x}\right)^{5}(2x2−3x1)5, in descending powers of xxx.[3]▸ Answer(ii)Hence find the coefficient of x7x^{7}x7 in the expansion of (3+1x3)(2x2−13x)5\left(3 + \tfrac{1}{x^{3}}\right)\left(2x^{2} - \tfrac{1}{3x}\right)^{5}(3+x31)(2x2−3x1)5.[2]▸ Answer▸ Official mark scheme← 2.11: Binomial expansion: find nnn, aaa and bbb1.11: Binomial expansion and coefficient of x7x^7x7 →
