Additional Mathematics 0606 / Series / 1.191.19: Binomial expansion and term independent of xxx0606/13/O/N/16 — Question 4 · 6 marks · BinomialMark as done · Save for later · Show all solutions(i)Find, in ascending powers of xxx, the first 3 terms in the expansion of (2−x4)6\left(2 - \tfrac{x}{4}\right)^{6}(2−4x)6.[3]▸ Answer(ii)Hence find the term independent of xxx in the expansion of (4+2x+3x2)(2−x4)6\left(4 + \tfrac{2}{x} + \tfrac{3}{x^{2}}\right)\left(2 - \tfrac{x}{4}\right)^{6}(4+x2+x23)(2−4x)6.[3]▸ Answer▸ Official mark scheme← 1.11: Binomial expansion and coefficient of x7x^7x71.7: Binomial expansion with negative powers of xxx →
