Additional Mathematics 0606 / Series / 1.221.22: Binomial expansion: find nnn0606/13/O/N/20 — Question 5 · 5 marks · BinomialMark as done · Save for later · Show all solutionsGiven that the coefficient of x2x^{2}x2 in the expansion of (1+x)(1−x2)n(1+x)\left(1 - \tfrac{x}{2}\right)^{n}(1+x)(1−2x)n is 254\tfrac{25}{4}425, find the value of the positive integer nnn.[5]▸ Answer▸ Official mark scheme← 1.16: Coefficient of x2x^2x2 in a binomial product2.6: Binomial product: find aaa, bbb and ccc →