2.14: Binomial product: find aa, bb and cc

0606/23/O/N/19 — Question 3 · 8 marks · Binomial

The first four terms in the expansion of (1+ax)5(2+bx)(1 + ax)^{5}(2 + bx) are 2+32x+210x2+cx32 + 32x + 210x^{2} + cx^{3}, where aa, bb and cc are integers. Show that 3a216a+21=03a^{2} - 16a + 21 = 0 and hence find the values of aa, bb and cc.
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