Target Mathematics

3.23: Trigonometric motion; AP product; exponential GP

0606/13/M/J/24 — Question 9 · 15 marks

(a)
A particle PP moves in a straight line such that, tt seconds after leaving a fixed point OO, its displacement ss metres is given by s=4t4cos2t+4s=4t-4\mathrm{cos}\,2t+4.
Find the velocity, vv, of PP at time tt.
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(b)
On the axes, sketch the velocity–time graph for PP for 0tπ0\leqslant t\leqslant\pi, stating the intercepts with the axes in exact form.
[5]
(c)
Find the acceleration of PP at time tt.
[1]
(d)
Find the times when the acceleration of PP is zero for 0tπ0\leqslant t\leqslant\pi.
[2]
(a)(i)
An AP has first three terms summing to 4242 and product 6720-6720. Show a(a+2d)=480a(a+2d)=-480.
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(a)(ii)
Given that a>0a>0, find the value of aa and of dd.
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(b)
A geometric progression has third term e4x4\dfrac{\mathrm{e}^{4x}}{4} and tenth term e11x512\dfrac{\mathrm{e}^{11x}}{512}. Find the first term and the common ratio.
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