Additional Mathematics 0606 / Series / 3.293.29: GP common ratio in terms of kkk0606/12/M/J/25 — Question 7 · 7 marksMark as done · Save for later · Show all solutions(a)A GP has 444th term 827k6\dfrac{8}{27}k^{6}278k6 and 666th term 32243k10\dfrac{32}{243}k^{10}24332k10, with r>0r>0r>0. Find rrr in terms of kkk and the first term.[4]▸ Answer(b)Given S∞=3S_{\infty}=3S∞=3, find the possible values of kkk.[3]▸ Answer▸ Official mark scheme← 3.85: Term independent of xxx in a product of expansions3.31: Logarithmic AP inequality and 25th term →