3.29: GP common ratio in terms of kk

0606/12/M/J/25 — Question 7 · 7 marks

(a)
A GP has 44th term 827k6\dfrac{8}{27}k^{6} and 66th term 32243k10\dfrac{32}{243}k^{10}, with r>0r>0. Find rr in terms of kk and the first term.
[4]
(b)
Given S=3S_{\infty}=3, find the possible values of kk.
[3]