Additional Mathematics 0606 / Series / 3.363.36: GP with S4=17S2S_4=17S_2S4=17S20606/13/O/N/21 — Question 5 · 6 marksMark as done · Save for later · Show all solutions(a)A GP has S4=17S2S_{4}=17S_{2}S4=17S2 with r>0r>0r>0, r≠1r\neq1r=1. Find rrr.[3]▸ Answer(b)Given the 666th term is 646464, find the first term.[2]▸ Answer(c)Explain why this GP does not have a sum to infinity.[1]▸ Answer▸ Official mark scheme← 3.35: Binomial expansion in powers of x2x^{2}x23.37: Normal to a curve; AP and GP with shared form →
