Additional Mathematics 0606 / Simultaneous equations and quadratics / 2.112.11: Logarithmic equations with base 20606/23/O/N/18 — Question 6 · 5 marksMark as done · Save for later · Show all solutionsSolve the simultaneous equationslog2(x+2y)=3\log_{2}(x + 2y) = 3log2(x+2y)=3log23x−log2y=1\log_{2} 3x - \log_{2} y = 1log23x−log2y=1[5]▸ Answer▸ Official mark scheme← 2.8: Index equations in ppp and qqq1.1: Linear and circle equation →