Additional Mathematics 0606 / Simultaneous equations and quadratics / 2.132.13: Index equations in xxx and yyy0606/23/O/N/20 — Question 5 · 5 marksMark as done · Save for later · Show all solutionsSolve the following simultaneous equations.3x×9y−1=2433^{x} \times 9^{y - 1} = 2433x×9y−1=2438×2y−12=22x+1428 \times 2^{y - \frac{1}{2}} = \frac{2^{2x + 1}}{4\sqrt{2}}8×2y−21=4222x+1[5]▸ Answer▸ Official mark scheme← 2.12: Quadratic and linear simultaneous equations2.1: Simultaneous equations with powers of 10 →
