Additional Mathematics 0606 / Simultaneous equations and quadratics / 3.73.7: Modulus graphs and inequality from intersections0606/23/O/N/21 — Question 1 · 6 marksMark as done · Save for later · Show all solutions(a)On the axes draw the graphs of y=∣x−5∣y = \lvert x - 5 \rverty=∣x−5∣ and y=6−∣2x−7∣y = 6 - \lvert 2x - 7 \rverty=6−∣2x−7∣.[4]▸ Answer(b)Use your graphs to solve the inequality ∣x−5∣⩾6−∣2x−7∣\lvert x - 5 \rvert \geqslant 6 - \lvert 2x - 7 \rvert∣x−5∣⩾6−∣2x−7∣.[2]▸ Answer▸ Official mark scheme← 3.6: Exponential simultaneous equations and a linear exponent equation3.8: Linear simultaneous equations with surds →
