Additional Mathematics 0606 / Simultaneous equations and quadratics / 3.173.17: Index equation reducing to y=3xy = 3xy=3x0606/11/O/N/24 — Question 2 · 5 marksMark as done · Save for later · Show all solutions(a)Given that 256x+y×16−2x=8−x+3y256^{x + y} \times 16^{-2x} = 8^{-x + 3y}256x+y×16−2x=8−x+3y, show that y=3xy = 3xy=3x.[2]▸ Answer(b)Hence find the exact solutions of the following simultaneous equations.256x+y×16−2x=8−x+3y256^{x + y} \times 16^{-2x} = 8^{-x + 3y}256x+y×16−2x=8−x+3yx2+3y2=56x^{2} + 3y^{2} = 56x2+3y2=56[3]▸ Answer▸ Official mark scheme← 3.3: Fractional powers and logarithmic simultaneous equations3.18: Power simultaneous equations in xxx and yyy →
