Additional Mathematics 0606 / Straight-line graphs / 1.21.2: Equation of a perpendicular bisector0606/11/M/J/18 — Question 2 · 5 marksMark as done · Save for later · Show all solutionsFind the equation of the perpendicular bisector of the line joining the points (1,3)(1, 3)(1,3) and (4,−5)(4, -5)(4,−5). Give your answer in the form ax+by+c=0ax + by + c = 0ax+by+c=0, where aaa, bbb and ccc are integers.[5]▸ Answer▸ Official mark scheme← 2.19: Linear law: y2y^{2}y2 against e2xe^{2x}e2x1.10: Linear law: eye^{y}ey against x2x^{2}x2 →