Additional Mathematics 0606 / Straight-line graphs / 2.142.14: Linear law: y3\sqrt[3]{y}3y against 1x\dfrac{1}{x}x10606/23/M/J/17 — Question 3 · 4 marksMark as done · Save for later · Show all solutionsVariables xxx and yyy are such that when y3\sqrt[3]{y}3y is plotted against 1x\dfrac{1}{x}x1, a straight line graph passing through the points (0.2,5)(0.2, 5)(0.2,5) and (1,13)(1, 13)(1,13) is obtained.Express yyy in terms of xxx.[4]▸ Answer▸ Official mark scheme← 2.10: Line ABABAB; show angle ADCADCADC is a right angle1.5: Linear law: lny\ln ylny against xxx →