3.19: Normal to ln\ln curve; gradient of BCBC

0606/12/M/J/22 — Question 9 · 9 marks

The normal to the curve y=ln ⁣(x2+3)+12x2y=\ln\!\left(x^{2}+3\right)+\dfrac{1}{2}x^{2} at the point AA where x=0x=0 meets the xx-axis at BB. Point CC has coordinates (0,3ln2)(0, 3\ln 2). Find the gradient of the line BCBC in terms of ln2\ln 2.
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