Additional Mathematics 0606 / Straight-line graphs / 3.203.20: Exponential equation and simultaneous equations0606/13/M/J/22 — Question 3 · 8 marksMark as done · Save for later · Show all solutions(a)Find the exact solution of the equation 2e6x−3e3x−5=02e^{6x}-3e^{3x}-5=02e6x−3e3x−5=0.[3]▸ Answer(b)Solve the simultaneous equationsex+ey=4,xy=18.e^{x}+e^{y}=4,\qquad xy=18.ex+ey=4,xy=18.[5]▸ Answer▸ Official mark scheme← 3.90: Straight-line log graph for lg(2y+1)3.21: Linear law: e4ye^{4y}e4y against xxx →
