3.23: Logarithm equation (adjacent) then linear law

0606/21/M/J/22 — Question 2 · 6 marks

(a)
Write lg⁡x−lg⁡(x+2)+lg⁡6+lg⁡3\lg x-\lg(x+2)+\lg 6+\lg 3 as a single logarithm to base 1010.
[2]
(b)
Hence solve lg⁡x−lg⁡(x+2)+lg⁡6+lg⁡3=0\lg x-\lg(x+2)+\lg 6+\lg 3=0.
[4]