Additional Mathematics 0606 / Straight-line graphs / 3.393.39: Linear law: e2ye^{2y}e2y against x3x^{3}x30606/13/M/J/24 — Question 5 · 6 marksMark as done · Save for later · Show all solutions(a)When e2ye^{2y}e2y is plotted against x3x^{3}x3, a straight line through (2,5)(2, 5)(2,5) and (6.4,7.2)(6.4, 7.2)(6.4,7.2) is obtained. Find yyy in terms of xxx.[4]▸ Answer(b)Find the values of xxx for which yyy exists.[2]▸ Answer▸ Official mark scheme← 3.38: Exact integral ∫02ex2/2 dx\int_0^2 e^{x^{2}/2}\,\mathrm{d}x∫02ex2/2dx form3.40: Linear law: lny\ln ylny against xxx for y=Aekxy=Ae^{kx}y=Aekx →