Additional Mathematics 0606 / Straight-line graphs / 3.483.48: Linear law: yyy against x3x^{3}x30606/23/M/J/25 — Question 3 · 4 marksMark as done · Save for later · Show all solutionsVariables xxx and yyy are such that when yyy is plotted against x3x^{3}x3 a straight line through (2,5)(2, 5)(2,5) and (10,21)(10, 21)(10,21) is obtained. Find yyy in terms of xxx.[4]▸ Answer▸ Official mark scheme← 3.46: Permutations of members (tagged SLG paper)3.71: Cubic polynomial with derivative and factor conditions →