Additional Mathematics 0606 / Straight-line graphs / 3.723.72: Linear law: e5ye^{5y}e5y against x3x^{3}x30606/11/O/N/24 — Question 7 · 8 marksMark as done · Save for later · Show all solutions(a)When e5ye^{5y}e5y is plotted against x3x^{3}x3, a straight line through (−2.56,4.38)(-2.56, 4.38)(−2.56,4.38) and (6.54,9.84)(6.54, 9.84)(6.54,9.84) is obtained. Find yyy in terms of xxx.[5]▸ Answer(b)Find the values of xxx for which yyy can exist.[3]▸ Answer▸ Official mark scheme← 3.71: Cubic polynomial with derivative and factor conditions3.73: Tangent meets axes; mid-point of XYXYXY →