Additional Mathematics 0606 / Straight-line graphs / 3.853.85: Exponential model from a straight-line graph0606/12/M/J/25 — Question 6 · 6 marksMark as done · Save for later · Show all solutions(a)When lny\ln ylny is plotted against x3x^{3}x3, a straight line through (2,5)(2,5)(2,5) and (−8,25)(-8,25)(−8,25) is obtained. Find yyy in terms of xxx.[4]▸ Answer(b)Find xxx when y=e25y=\mathrm{e}^{25}y=e25.[2]▸ Answer▸ Official mark scheme← 3.43: Polynomial factors then exponential equation3.46: Permutations of members (tagged SLG paper) →