Additional Mathematics 0606 / Trigonometry / 1.21.2: Pythagorean identity with tan and sec0606/11/M/J/17 — Question 9 · 1 markMark as done · Save for later · Show all solutions(i)Show that 5+4tan2(x3)=4sec2(x3)+15 + 4\tan^{2}\left(\tfrac{x}{3}\right) = 4\sec^{2}\left(\tfrac{x}{3}\right) + 15+4tan2(3x)=4sec2(3x)+1.[1]▸ Answer▸ Official mark scheme← 2.29: Cosecant identity and mixed equations1.11: Cosec over cot plus tan identity →
