Additional Mathematics 0606 / Trigonometry / 1.71.7: Cosec–sin and tangent equations0606/11/O/N/17 — Question 10 · 8 marksMark as done · Save for later · Show all solutions(a)Solve 3csc2x−4sin2x=03\csc 2x - 4\sin 2x = 03csc2x−4sin2x=0 for 0°≤x≤180°0^{\degree} \le x \le 180^{\degree}0°≤x≤180°.[4]▸ Answer(b)Solve 3tan(y−π4)=33\tan\left(y - \tfrac{\pi}{4}\right) = \sqrt{3}3tan(y−4π)=3 for 0≤y≤2π0 \le y \le 2\pi0≤y≤2π radians, giving your answers in terms of π\piπ.[4]▸ Answer▸ Official mark scheme← 2.24: Quadratic in sin and tan–sin equation1.16: Sine curve constants from amplitude and period →
