Additional Mathematics 0606 / Trigonometry / 1.251.25: Tangent–sine identity and parametric elimination0606/13/M/J/17 — Question 7 · 7 marksMark as done · Save for later · Show all solutions(a)Show that tan2θ+sin2θcosθ+secθ=tanθsinθ\tfrac{\tan^{2}\theta + \sin^{2}\theta}{\cos \theta + \sec \theta} = \tan \theta \sin \thetacosθ+secθtan2θ+sin2θ=tanθsinθ.[4]▸ Answer(b)Given that x=3sinϕx = 3\sin \phix=3sinϕ and y=3cosϕy = \tfrac{3}{\cos \phi}y=cosϕ3, find the numerical value of 9y2−x2y29y^{2} - x^{2}y^{2}9y2−x2y2.[3]▸ Answer▸ Official mark scheme← 1.24: Sine graph sketch and modulus range2.2: Cosine curve properties and graph equation →