Additional Mathematics 0606 / Trigonometry / 2.222.22: Sin–tan identity and sec–cot equation0606/22/O/N/20 — Question 11 · 10 marksMark as done · Save for later · Show all solutions(a)Show that sinxtanx1−cosx=1+secx\dfrac{\sin x \tan x}{1 - \cos x} = 1 + \sec x1−cosxsinxtanx=1+secx.[4]▸ Answer(b)Solve the equation 5tanx−3cotx=2secx5\tan x - 3\cot x = 2\sec x5tanx−3cotx=2secx for 0°≤x≤360°0^{\degree} \le x \le 360^{\degree}0°≤x≤360°.[6]▸ Answer▸ Official mark scheme← 2.21: Exact triangle area and cosine rule1.5: Period and sketch of a cosine graph →
