Target Mathematics

3.10: Polynomial factors then cosec equation

0606/12/F/M/24 — Question 5 · 13 marks

The polynomial pp is such that p(x)=5x3+ax2+39x+bp(x) = 5x^{3} + ax^{2} + 39x + b, where aa and bb are constants.
(a)
Given that x+3x + 3 is a factor of both p(x)p(x) and p(x)p'(x), find the values of aa and bb.
[5]
(b)
Hence solve the equation p(x)=0p(x) = 0. You must show your working.
[3]
(c)
Hence, using your values for aa and bb, solve the equation
5cosec3θ+acosec2θ+39cosecθ+b=05\,\mathrm{cosec}^{3}\theta + a\,\mathrm{cosec}^{2}\theta + 39\,\mathrm{cosec}\,\theta + b = 0
for 0θ3600^{\circ} \leqslant \theta \leqslant 360^{\circ}.
[5]