Additional Mathematics 0606 / Trigonometry / 3.1043.104: Cot and cosec equation0606/22/O/N/24 — Question 8 · 6 marksMark as done · Save for later · Show all solutionsSolve the equation cot2θ+cosec 2θ=9\mathrm{cot}^{2}\theta + \mathrm{cosec}\,2\theta = 9cot2θ+cosec2θ=9 for −90∘⩽θ⩽90∘-90^{\circ} \leqslant \theta \leqslant 90^{\circ}−90∘⩽θ⩽90∘.[6]▸ Answer▸ Official mark scheme← 3.103: Selections including Abby and Ben3.105: Binomial terms equal →
