Additional Mathematics 0606 / Trigonometry / 3.1143.114: Solve 3sin2(2x+π/4)=cos2(2x+π/4)3\sin^{2}(2x+\pi/4)=\cos^{2}(2x+\pi/4)3sin2(2x+π/4)=cos2(2x+π/4)0606/12/O/N/22 — Question 4 · 5 marksMark as done · Save for later · Show all solutionsSolve the equation 3 sin2(2x+π4)=cos2(2x+π4)3\,\mathrm{sin}^{2}\left(2x+\dfrac{\pi}{4}\right)=\mathrm{cos}^{2}\left(2x+\dfrac{\pi}{4}\right)3sin2(2x+4π)=cos2(2x+4π) for 0⩽x⩽π0\leqslant x\leqslant\pi0⩽x⩽π.[5]▸ Answer▸ Official mark scheme← 3.73: Sine graph: find a, b, c3.74: Sketch y=4−3sin2xy=4-3\sin 2xy=4−3sin2x →
