Additional Mathematics 0606 / Trigonometry / 3.133.13: Tan given: cos, sin, sec + cot0606/12/F/M/25 — Question 6 · 5 marksMark as done · Save for later · Show all solutionsIt is given that tan θ=55\mathrm{tan}\,\theta = \dfrac{\sqrt{5}}{5}tanθ=55 and 180∘<θ<360∘180^{\circ} < \theta < 360^{\circ}180∘<θ<360∘.(a)Find the value of cos θ\mathrm{cos}\,\thetacosθ.[2]▸ Answer(b)Find the value of sin θ\mathrm{sin}\,\thetasinθ.[1]▸ Answer(c)Find the value of sec θ+cot θ\mathrm{sec}\,\theta + \mathrm{cot}\,\thetasecθ+cotθ. Give your answer in the form a+bc5\dfrac{a + b\sqrt{c}}{\sqrt{5}}5a+bc, where aaa, bbb and ccc are integers.[2]▸ Answer▸ Official mark scheme← 3.12: Completing the square and inverse of a quadratic3.14: Composite exponential function →