Additional Mathematics 0606 / Trigonometry / 3.193.19: Polynomial factor and remainder0606/22/M/J/21 — Question 4 · 6 marksMark as done · Save for later · Show all solutionsThe polynomial p(x)=mx3−29x2+39x+n\mathrm{p}(x)=mx^{3}-29x^{2}+39x+np(x)=mx3−29x2+39x+n, where mmm and nnn are constants, has a factor x−13x-\tfrac{1}{3}x−31, and remainder 666 when divided by x−1x-1x−1. Show that x−2x-2x−2 is a factor of p(x)\mathrm{p}(x)p(x).[6]▸ Answer▸ Official mark scheme← 3.18: Logarithmic equations and identities3.20: Cosine: amplitude, period and sketch →