Additional Mathematics 0606 / Trigonometry / 3.213.21: Ln curve sketch and tangent0606/23/M/J/21 — Question 7 · 7 marksMark as done · Save for later · Show all solutions(a)Sketch the graph of y=ln(4−3x)y = \ln(4 - 3x)y=ln(4−3x) on the axes, stating the intercept with the xxx-axis.[2]▸ Answer(b)Find the equation of the tangent to y=ln(4−3x)y = \ln(4 - 3x)y=ln(4−3x) at the point where x=1x = 1x=1.[5]▸ Answer▸ Official mark scheme← 3.20: Cosine: amplitude, period and sketch3.22: Integrals with sine and identity →