Additional Mathematics 0606 / Trigonometry / 3.303.30: Sec–cot identity and equation0606/11/M/J/23 — Question 6 · 10 marksMark as done · Save for later · Show all solutions(a)Show that sec θ+cot θ=tan θ+cosec θ\mathrm{sec}\,\theta + \mathrm{cot}\,\theta = \mathrm{tan}\,\theta + \mathrm{cosec}\,\thetasecθ+cotθ=tanθ+cosecθ.[4]▸ Answer(b)Hence solve sec 3θ+cot 3θ=2\mathrm{sec}\,3\theta + \mathrm{cot}\,3\theta = 2sec3θ+cot3θ=2 for −540∘⩽θ⩽540∘-540^{\circ} \leqslant \theta \leqslant 540^{\circ}−540∘⩽θ⩽540∘.[6]▸ Answer▸ Official mark scheme← 3.29: Triangles with exact trig ratios3.31: Cosine graph: find a, b, c →
