3.56: Small change for y=x2tan(x/2)y = x^{2}\tan(x/2)

0606/21/M/J/25 — Question 5 · 4 marks

Given that y=x2tanx2y = x^{2}\,\mathrm{tan}\dfrac{x}{2}, use calculus to find the approximate change in yy as xx increases from π3\dfrac{\pi}{3} to π3+h\dfrac{\pi}{3} + h, where hh is small.
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