Additional Mathematics 0606 / Trigonometry / 3.583.58: Composite function equation0606/22/M/J/25 — Question 3 · 4 marksMark as done · Save for later · Show all solutionsFunctions f\mathrm{f}f and g\mathrm{g}g are such thatf(x)=4x2+3(x⩾0),g(x)=2−x2.\mathrm{f}(x) = \dfrac{4}{x^{2} + 3}\quad(x \geqslant 0),\qquad \mathrm{g}(x) = 2 - x^{2}.f(x)=x2+34(x⩾0),g(x)=2−x2.Solve the equation fg(x)=1\mathrm{fg}(x) = 1fg(x)=1.[4]▸ Answer▸ Official mark scheme← 3.57: Exponential function and inverse sketch3.59: Derivative of product and normal →
