Additional Mathematics 0606 / Trigonometry / 3.663.66: Derivative of tan squared0606/21/O/N/21 — Question 5 · 7 marksMark as done · Save for later · Show all solutionsIt is given that y=tan23xy = \mathrm{tan}^{2} 3xy=tan23x for 0∘<x<360∘0^{\circ} < x < 360^{\circ}0∘<x<360∘.(a)Show that dydx=m tan 3x sec23x\dfrac{\mathrm{d}y}{\mathrm{d}x} = m\,\mathrm{tan}\,3x\,\mathrm{sec}^{2} 3xdxdy=mtan3xsec23x where mmm is an integer to be found.[2]▸ Answer(b)Find all values of xxx such that dydx=3 sec x cosec x\dfrac{\mathrm{d}y}{\mathrm{d}x} = 3\,\mathrm{sec}\,x\,\mathrm{cosec}\,xdxdy=3secxcosecx.[5]▸ Answer▸ Official mark scheme← 3.65: Rationalising a surd expression3.67: Binomial expansion and coefficient equation →
