Additional Mathematics 0606 / Trigonometry / 3.863.86: Secant equation in radians0606/12/O/N/23 — Question 5 · 5 marksMark as done · Save for later · Show all solutionsSolve the equation sec(3θ−π6)=4\mathrm{sec}\left(3\theta-\dfrac{\pi}{6}\right)=4sec(3θ−6π)=4 for −π2⩽θ⩽π2-\dfrac{\pi}{2} \leqslant \theta \leqslant \dfrac{\pi}{2}−2π⩽θ⩽2π, giving your answers in terms of π\piπ.[5]▸ Answer▸ Official mark scheme← 3.85: Binomial expansion first four terms3.87: Perpendicular bisector through a point →
