Additional Mathematics 0606 / Trigonometry / 3.923.92: Exact definite integral0606/23/O/N/23 — Question 4 · 6 marksMark as done · Save for later · Show all solutionsFind the exact value of ∫13(2x−3)5 dx\displaystyle\int_{1}^{3}(2x-3)^{5}\,\mathrm{d}x∫13(2x−3)5dx.[6]▸ Answer▸ Official mark scheme← 3.91: Further trigonometry / calculus3.93: Triangle with given angles (no calculator) →
