1.7: Unit vectors, constants and collinear points

0606/13/M/J/20 — Question 6 · 8 marks

(a)
Find the unit vector in the direction of (512)\begin{pmatrix} 5 \\ -12 \end{pmatrix}.
[1]
(b)
Given that (41)+k(23)=r(105)\begin{pmatrix} 4 \\ 1 \end{pmatrix} + k\begin{pmatrix} -2 \\ 3 \end{pmatrix} = r\begin{pmatrix} -10 \\ 5 \end{pmatrix}, find the value of each of the constants kk and rr.
[3]
(c)(i)
Relative to an origin OO, the points AA, BB and CC have position vectors p\mathbf{p}, 3qp3\mathbf{q} - \mathbf{p} and 9q5p9\mathbf{q} - 5\mathbf{p} respectively.
Find AB\overrightarrow{AB} in terms of p\mathbf{p} and q\mathbf{q}.
[1]
(c)(ii)
Find AC\overrightarrow{AC} in terms of p\mathbf{p} and q\mathbf{q}.
[1]
(c)(iii)
Explain why AA, BB and CC all lie in a straight line.
[1]
(c)(iv)
Find the ratio AB:BCAB:BC.
[1]