2.9: Triangle with cevians meeting at a point

0606/23/M/J/19 — Question 10 · 9 marks

2.9 diagram
The diagram shows a triangle OABOAB. The point PP is the midpoint of OAOA and the point QQ lies on OBOB such that OQ=14OB\overrightarrow{OQ} = \frac{1}{4}\overrightarrow{OB}. The position vectors of PP and QQ relative to OO are p\mathbf{p} and q\mathbf{q} respectively.
(i)
Find, in terms of p\mathbf{p} and q\mathbf{q}, an expression for each of the vectors PQ\overrightarrow{PQ}, QA\overrightarrow{QA} and PB\overrightarrow{PB}.
[3]
(ii)
Given that PR=λPB\overrightarrow{PR} = \lambda\overrightarrow{PB} and that QR=μQA\overrightarrow{QR} = \mu\overrightarrow{QA}, find an expression for PQ\overrightarrow{PQ} in terms of λ\lambda, μ\mu, p\mathbf{p} and q\mathbf{q}.
[2]
(iii)
Using your expressions for PQ\overrightarrow{PQ}, find the value of λ\lambda and of μ\mu.
[4]