3.4: Particle path and section formula in a triangle

0606/12/F/M/23 — Question 9 · 8 marks

3.4 diagram
In this question, all lengths are in metres.
(a)(i)
A particle PP has position vector (2+12t55t)\begin{pmatrix} 2 + 12t \\ 5 - 5t \end{pmatrix} at time tt seconds, t0t \geqslant 0.
Write down the initial position vector of PP.
[1]
(a)(ii)
Find the speed of PP.
[2]
(a)(iii)
Determine whether PP passes through the point with position vector (15848)\begin{pmatrix} 158 \\ -48 \end{pmatrix}.
[2]
(b)
The diagram shows triangle OACOAC. Point BB lies on ACAC such that AB:AC=1:4AB:AC = 1:4. Given OA=a\overrightarrow{OA} = \mathbf{a}, OB=b\overrightarrow{OB} = \mathbf{b} and OC=c\overrightarrow{OC} = \mathbf{c}, find c\mathbf{c} in terms of a\mathbf{a} and b\mathbf{b}.
[3]