Additional Mathematics 0606 / Vectors / 3.213.21: Displacement RQ and linear dependence of vectors0606/11/M/J/25 — Question 1 · 5 marksMark as done · Save for later · Show all solutions(a)Given that PQ→=(−37)\overrightarrow{PQ} = \begin{pmatrix} -3 \\ 7 \end{pmatrix}PQ=(−37) and 4PR→=(−28)4\overrightarrow{PR} = \begin{pmatrix} -2 \\ 8 \end{pmatrix}4PR=(−28), find RQ→\overrightarrow{RQ}RQ.[2]▸ Answer(b)The vectors a=ai+6j\mathbf{a} = a\mathbf{i} + 6\mathbf{j}a=ai+6j, b=4i+bj\mathbf{b} = 4\mathbf{i} + b\mathbf{j}b=4i+bj and c=(2a+5b)i+20j\mathbf{c} = (2a + 5b)\mathbf{i} + 20\mathbf{j}c=(2a+5b)i+20j satisfy c=3a−2b\mathbf{c} = 3\mathbf{a} - 2\mathbf{b}c=3a−2b. Find aaa and bbb.[3]▸ Answer▸ Official mark scheme← 3.36: Two particles and no-collision argument3.45: Vector geometry: lines PQPQPQ and OBOBOB →
