3.40: Section formula and vector equation for m,nm,n

0606/12/O/N/21 — Question 7 · 8 marks

3.40 diagram
The diagram shows triangle OACOAC with OA=a\overrightarrow{OA} = \mathbf{a}, OB=b\overrightarrow{OB} = \mathbf{b}, OC=c\overrightarrow{OC} = \mathbf{c}. Point BB lies on ACAC with AB:BC=m:nAB:BC = m:n.
(a)(i)
Write down AB\overrightarrow{AB} in terms of a\mathbf{a} and b\mathbf{b}.
[1]
(a)(ii)
Write down BC\overrightarrow{BC} in terms of b\mathbf{b} and c\mathbf{c}.
[1]
(a)(iii)
Hence show that b=na+mcm+n\mathbf{b} = \dfrac{n\mathbf{a} + m\mathbf{c}}{m + n}.
[2]
(b)
Given the printed vector equation in mm and nn, find mm and nn.
[4]