3.47: Vector geometry in triangle OABOAB

0606/13/M/J/23 — Question 8 · 10 marks

3.47 diagram3.47 diagram
(a)
The diagram shows triangle OABOAB with OA=a\overrightarrow{OA}=\mathbf{a} and OB=b\overrightarrow{OB}=\mathbf{b}. Point XX lies on OAOA with OX=35a\overrightarrow{OX}=\tfrac{3}{5}\mathbf{a}. Point YY is the mid-point of ABAB.
Find AB\overrightarrow{AB} in terms of a\mathbf{a} and b\mathbf{b}.
[1]
(b)
Find XY\overrightarrow{XY} in terms of a\mathbf{a} and b\mathbf{b}.
[2]
(c)
The lines OBOB and XYXY extended meet at ZZ. Given YZ=mXY\overrightarrow{YZ}=m\overrightarrow{XY} and BZ=nb\overrightarrow{BZ}=n\mathbf{b}, find XZ\overrightarrow{XZ} in terms of mm, a\mathbf{a} and b\mathbf{b}.
[2]
(d)
Find XZ\overrightarrow{XZ} in terms of nn, a\mathbf{a} and b\mathbf{b}.
[2]
(e)
Hence find the values of mm and nn.
[3]