Additional Mathematics 0606 / Logarithms and Exponents / 1.21.2: Single logarithm and a quadratic in log a 50606/11/M/J/18 — Question 6 · 6 marks · Log laws, Change of base, EquationsMark as done · Save for later · Show all solutions(a)Write (log2p)(log32)+log3q(\log_{2} p)(\log_{3} 2) + \log_{3} q(log2p)(log32)+log3q as a single logarithm to base 333.[3]▸ Answer(b)Given that (loga5)2−4loga5+3=0(\log_{a} 5)^{2} - 4\log_{a} 5 + 3 = 0(loga5)2−4loga5+3=0, find the possible values of aaa.[3]▸ Answer← 1.1: Exponential population model1.3: Logarithmic equations with bases 3, 9 and 4 →
