Additional Mathematics 0606 / Logarithms and Exponents / 1.111.11: Value of xy; exponential equation by substitution0606/13/M/J/20 — Question 2 · 7 marks · Change of base, Exponentials, EquationsMark as done · Save for later · Show all solutions(a)Given that log2x+2log4y=8\log_{2} x + 2\log_{4} y = 8log2x+2log4y=8, find the value of xyxyxy.[3]▸ Answer(b)Using the substitution y=2xy = 2^{x}y=2x, or otherwise, solve22x+1−2x+1−2x+1=0.2^{2x+1} - 2^{x+1} - 2^{x} + 1 = 0.22x+1−2x+1−2x+1=0.[4]▸ Answer← 1.10: Single logarithm and a quadratic in log a 5 (repeat)1.12: Simultaneous equations in log x and log y →
