Additional Mathematics 0606 / Logarithms and Exponents / 2.22.2: Binomial expansion applied to an exponential equation0606/21/M/J/20 — Question 8 · 7 marks · Binomial, Exponentials, EquationsMark as done · Save for later · Show all solutions(a)Expand (2−x)5(2 - x)^{5}(2−x)5, simplifying each coefficient.[3]▸ Answer(b)Hence solve e(2−x)5×e80xe10x4+32=e−x5\dfrac{e^{(2-x)^{5}} \times e^{80x}}{e^{10x^{4}} + 32} = e^{-x^{5}}e10x4+32e(2−x)5×e80x=e−x5.[4]▸ Answer← 2.1: Logarithm evaluations without a calculator2.3: Equation in lg x →
