Additional Mathematics 0606 / Logarithms and Exponents / 2.102.10: Index equation; solve log a b minus half equals log b a0606/22/M/J/20 — Question 9 · 8 marks · Indices, Equations, Change of baseMark as done · Save for later · Show all solutions(a)Solve the equation 95x27x−2=243\dfrac{9^{5x}}{27^{x - 2}} = 24327x−295x=243.[3]▸ Answer(b)logab−12=logba\log_{a} b - \dfrac{1}{2} = \log_{b} alogab−21=logba, where a>0a > 0a>0 and b>0b > 0b>0. Solve this equation for bbb, giving your answers in terms of aaa.[5]▸ Answer← 2.9: Logs from a power relation; two index equations2.11: Equation in lg x (repeat) →
