Additional Mathematics 0606 / Logarithms and Exponents / 2.132.13: Exponential equation; log equation with reciprocal0606/22/O/N/18 — Question 4 · 8 marks · Exponentials, Equations, Change of baseMark as done · Save for later · Show all solutions(i)Solve 23x−1=62^{3x - 1} = 623x−1=6.[3]▸ Answer(ii)Solve log3(y+14)=1+2logy3\log_{3}(y + 14) = 1 + \dfrac{2}{\log_{y} 3}log3(y+14)=1+logy32.[5]▸ Answer← 2.12: Equation with fractional indices2.14: Equation with powers of 2, matching indices →
