Additional Mathematics 0606 / Logarithms and Exponents / 3.43.4: Log laws for a and reciprocal-base equation0606/12/F/M/24 — Question 2 · 7 marks · Log laws, Change of base, EquationsMark as done · Save for later · Show all solutions(a)Given that logpa+logp12−logp6=3logp4\log_{p} a + \log_{p} 12 - \log_{p} 6 = 3\log_{p} 4logpa+logp12−logp6=3logp4, find the value of aaa.[3]▸ Answer(b)Find the exact solutions of the equation 4log3x=9logx34\log_{3} x = 9\log_{x} 34log3x=9logx3.[4]▸ Answer▸ Official mark scheme← 3.3: Single lg and equation with reciprocal logs3.5: Normal to y = ln(x³ + 3) →
