Additional Mathematics 0606 / Logarithms and Exponents / 3.73.7: Equation with log base 2 and reciprocal base0606/12/F/M/25 — Question 9 · 5 marks · Change of base, EquationsMark as done · Save for later · Show all solutionsSolve the equation log2(x+1)−4log(x+1)2=3\log_{2}(x + 1) - 4\log_{(x + 1)} 2 = 3log2(x+1)−4log(x+1)2=3.[5]▸ Answer▸ Official mark scheme← 3.6: Definite integrals with fractional powers and ln3.8: Straight line for e^y against x² →